The magnetic flux is proportional to the number of
field lines that pass through the surface.
Φ = Bn A
- Φ magnetic flux in Wb (Weber). Also : T m2 of Vs
- Bn the component of B perpendicular to the surface in T(esla)
- A area of the surface in m2
Example
See the drawing above.
B = 1.5 x 10-3 T
A = 500 cm2
α = 40 o
Resolve B in both components and calculate Bn
sin α = Bn/B
Bn = B sin 40 o = (1.5 x 10-3)( 0.643) = 9.642 x 10-4 T
Φ = Bn A
Φ = (9.642 x 10-4 )( 500 x 10-4)= 4.82 x 10-5 Wb